Calculus

Problem 28601

Find the velocity equation in ms1\mathrm{ms}^{-1} from the displacement model x=Acos(ωt)+Bsin(ωt)x=A \cos (\omega t)+B \sin (\omega t) at time tt.

See Solution

Problem 28602

Determine the arc length function for f(x)=x312+1xf(x)=\frac{x^{3}}{12}+\frac{1}{x} from point A=(1,1312)A=(1,\frac{13}{12}).

See Solution

Problem 28603

Bestimme die Extrempunkte der Funktionen: a) f(x)=2xexf(x)=2 x-e^{x}, b) f(x)=x2e2xf(x)=x^{2} \cdot e^{2 x}.

See Solution

Problem 28604

Find the curve length for x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} dt, π/4yπ/4-\pi / 4 \leq y \leq \pi / 4. a-2. b-4. c-8. d-None

See Solution

Problem 28605

Calculate the curve length of y=(x/2)2/3y=(x / 2)^{2 / 3} from x=0x=0 to x=2x=2. Options: a) 227(101)\frac{2}{27}(\sqrt{10}-1) b) 272(1+10)\frac{27}{2}(1+\sqrt{10}) c) 274(10101)\frac{27}{4}(10 \sqrt{10}-1) d) 227(10101)\frac{2}{27}(10 \sqrt{10}-1)

See Solution

Problem 28606

Find the curve length for x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} dt, with π/4yπ/4-\pi / 4 \leq y \leq \pi / 4. Options: a-2, b-4, c-8, d-None.

See Solution

Problem 28607

Find the slope of the inverse function g1g^{-1} at the origin if g(0)=0g(0)=0 and g(0)=2g'(0)=2. Options: a-2, b-0, c-1/2, d-undefined, e-None.

See Solution

Problem 28608

Sia ff derivabile in zero con f(0)=0f(0)=0 e f(0)=4f'(0)=4. Qual è il limite =limx0+f(x)1+1+6x\ell = \lim_{x \to 0^{+}} \frac{f(x)}{-1+\sqrt{1+6x}}? (a) C non esiste. (b) =0\ell=0. (c) =4/3\ell=4/3. (d) =4\ell=4. (e) Nessuna delle precedenti.

See Solution

Problem 28609

Find a curve through (1,1) with length L=12144x+1xdxL=\frac{1}{2} \int_{1}^{4} \sqrt{\frac{4x+1}{x}} dx. Options: a. x-\sqrt{x}, b. 12x\frac{1}{2x}, c. 12x-\frac{1}{2\sqrt{x}}, d. None.

See Solution

Problem 28610

Find the time tt when the particle at x(t)=16t3t3x(t)=16t-3t^{3} is momentarily at rest. Options: 51.30 s, 55.30 s, 57.3 s.

See Solution

Problem 28611

Oblicz granicę ciągu: limn(2n2+3n26)n\lim _{n \rightarrow \infty}\left(\frac{2 n^{2}+3}{n^{2}-6}\right)^{n}

See Solution

Problem 28612

Use the Ratio or Root Test on the series n=1n10(10)n+1\sum_{n=1}^{\infty} \frac{n^{10}}{(-10)^{n+1}}.

See Solution

Problem 28613

Find the length of the curve x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} dt for π/4yπ/4-\pi / 4 \leq y \leq \pi / 4.

See Solution

Problem 28614

Find the surface area from revolving y=1πsin(3x)y=\frac{1}{\pi} \sin (3 x), 0xπ60 \leq x \leq \frac{\pi}{6}, about the xx-axis.

See Solution

Problem 28615

Find where the function y=13(x+1)32y=\frac{1}{3}(x+1)^{3}-2 is increasing, decreasing, or constant.

See Solution

Problem 28616

Evaluate the integral I=01(6x5x2/3)dxI=\int_{0}^{1}(6x-5x^{2/3})dx. What is the value of II?

See Solution

Problem 28617

Find the limit: limx+sin(1x)x\lim _{x \rightarrow+\infty} \frac{\sin \left(\frac{1}{x}\right)}{x}. Choose one: does not exist, ++\infty, 1, 0.

See Solution

Problem 28618

Find the surface area of the curve y=1πsin(3x)y=\frac{1}{\pi} \sin (3 x) from 00 to π6\frac{\pi}{6} rotated about the xx-axis.

See Solution

Problem 28619

Oblicz granicę funkcji: limx0sin(3x2)x2sin3(x)\lim _{x \rightarrow 0} \frac{\sin \left(3 x^{2}\right)}{x^{2}-\sin ^{3}(x)} przy użyciu reguły de hospitala.

See Solution

Problem 28620

Find the surface area of the curve x=3yx=3 \sqrt{y}, for 19y29\frac{1}{9} \leq y \leq \frac{2}{9}, revolved about the yy-axis.

See Solution

Problem 28621

Estimate the following using linear approximation: 8. ln(1.1)\ln (1.1) 9. 8.9\sqrt{8.9} 10. sec(0.1)\sec (0.1)

See Solution

Problem 28622

Find the length of the curve y=25(x+3)5/2y=\frac{2}{5}(x+3)^{5/2} for 2x1-2 \leq x \leq -1. Choose the correct integral.

See Solution

Problem 28623

Find the length of the curve y=23(x+1)3/2y=\frac{2}{3}(x+1)^{3 / 2} for 4x54 \leq x \leq 5. Select the correct answer.

See Solution

Problem 28624

A Toyota Corolla's distance from a stop sign is x(t)=1.50t20.0500t3x(t)=1.50t^2-0.0500t^3. Find average velocity for: (a) t=0t=0 to t=2.00t=2.00 s, (b) t=0t=0 to t=4.00t=4.00 s, (c) t=2.00t=2.00 s to t=4.00t=4.00 s.

See Solution

Problem 28625

Is the function f(x)={x4625x225 if x525 if x=5f(x)=\left\{\begin{array}{c}\frac{x^{4}-625}{x^{2}-25} \text { if } x \neq 5 \\ 25 \text { if } x=5\end{array}\right. continuous at x=5x=5? If not, why?

See Solution

Problem 28626

Find the surface area of the curve y=1πsin(3x)y=\frac{1}{\pi} \sin (3 x) from 00 to π6\frac{\pi}{6} revolved around the xx-axis.

See Solution

Problem 28627

Find the linear approximation of g(z)=z4g(z)=\sqrt[4]{z} at z=2z=2 and use it to estimate 34\sqrt[4]{3} and 104\sqrt[4]{10}.

See Solution

Problem 28628

Calculate the limit: limx1x21x1\lim _{x \rightarrow 1^{-}} \frac{\left|x^{2}-1\right|}{x-1}. Options: (1) -2, 0, 2, ++\infty.

See Solution

Problem 28629

Find the limit as xx approaches 2 from the left for [x]x\frac{[x]}{x}. What is the value?

See Solution

Problem 28630

Find the limit as xx approaches 2 from the left of [x]x\frac{[x]}{x}. What is the result? Options: 2, 1, 12\frac{1}{2}.

See Solution

Problem 28631

Find the surface area of the curve y=1πsin(3x)y=\frac{1}{\pi} \sin (3 x) from 00 to π6\frac{\pi}{6} revolved around the xx-axis.

See Solution

Problem 28632

Find the limit as xx approaches infinity for 3x2+x+12x3+x+3\frac{3x^2 + x + 1}{2x^3 + x + 3}.

See Solution

Problem 28633

Find the limit as xx approaches 2 from the left of the expression [x]x\frac{[x]}{x}. What is the value?

See Solution

Problem 28634

A car's distance from a light is x(t)=bt2c3x(t)=b t^{2}-c^{3} with b=2.40 m/s2b=2.40 \mathrm{~m/s}^{2} and c=0.120 m/s3c=0.120 \mathrm{~m/s}^{3}. Find: (a) average velocity from t=0t=0 to t=10.0 st=10.0 \mathrm{~s}, (b) instantaneous velocity at t=0,t=5.0 st=0, t=5.0 \mathrm{~s}, and t=10.0 st=10.0 \mathrm{~s}, (c) when is the car at rest again?

See Solution

Problem 28635

Calculate the average velocity of a car with x(t)=bt2ct3x(t)=bt^2-ct^3 for b=2.40 m/s2b=2.40 \mathrm{~m/s}^2, c=0.120 m/s3c=0.120 \mathrm{~m/s}^3 over given intervals.

See Solution

Problem 28636

A 0.18 kg0.18 \mathrm{~kg} pine cone falls from 14 m14 \mathrm{~m}. Find its speed without air resistance and work done by friction if it hits at 10.2 m/s10.2 \mathrm{~m/s}.

See Solution

Problem 28637

A car's distance from a light is x(t)=bt2ct3x(t)=b t^{2}-c t^{3} with b=2.40 m/s2b=2.40 \mathrm{~m/s}^{2} and c=0.120 m/s3c=0.120 \mathrm{~m/s}^{3}. Find: (a) average velocity from t=0t=0 to t=10.0 st=10.0 \mathrm{~s}, (b) instantaneous velocity at t=0,5.0,10.0 st=0, 5.0, 10.0 \mathrm{~s}, (c) time when car is again at rest.

See Solution

Problem 28638

Find the limit: limx3x2+x+12x3+x+3\lim _{x \rightarrow \infty} \frac{3 x^{2}+x+1}{2 x^{3}+x+3}. What is it?

See Solution

Problem 28639

Solve the equation y4y+4=0y^{\prime \prime}-4 y^{\prime}+4=0 with conditions y(0)=1y(0)=1 and y(0)=0y^{\prime}(0)=0.

See Solution

Problem 28640

Find the integral of the function exe^{\sqrt{x}}.

See Solution

Problem 28641

Bestimme die Ableitungsfunktion von f(x)=1xf(x)=\frac{1}{x} für x0x \neq 0. Was ist f(x)f'(x)?

See Solution

Problem 28642

Find the surface area generated by revolving the curve x=4yy2x=\sqrt{4y-y^{2}} from y=1y=1 to y=2y=2 around the y-axis.

See Solution

Problem 28643

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π4x=\frac{\pi}{4}.

See Solution

Problem 28644

Find the length of the curve defined by x=0ysec4t1dtx = \int_{0}^{y} \sqrt{\sec^{4}t - 1} \, dt from y=π3y = -\frac{\pi}{3} to y=π3y = \frac{\pi}{3}. Options: 232\sqrt{3}, none, 0, 3\sqrt{3}, 1.

See Solution

Problem 28645

Find the limit as xx approaches 2 from the left: limx2[x]x=\lim _{x \rightarrow 2^{-}} \frac{[x]}{x}=. Choose from 2, 1, 12\frac{1}{2}, 32\frac{3}{2}.

See Solution

Problem 28646

Find df1dx\frac{d f^{-1}}{d x} for f(x)=1(1x)2f(x)=\frac{1}{(1-x)^{2}} at x=14x=\frac{1}{4}, where x>1x>1. Choices: -4, 4, 14\frac{1}{4}, none, 14-\frac{1}{4}.

See Solution

Problem 28647

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π4x=\frac{\pi}{4}.

See Solution

Problem 28648

Find the length of the curve defined by x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec^4 t - 1} \, dt from y=π3y=-\frac{\pi}{3} to y=π6y=\frac{\pi}{6}. Options: none, 0, 232\sqrt{3}, 433\frac{4\sqrt{3}}{3}, 1.

See Solution

Problem 28649

Find the surface area generated by revolving x=yx=\sqrt{y}, for 2y62 \leq y \leq 6, around the yy-axis.

See Solution

Problem 28650

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4,f(4)=5,f(2)=13,f(5)=15f(2)=4, f(4)=5, f^{\prime}(2)=\frac{1}{3}, f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28651

Find the surface area generated by revolving the curve x=24yx=2 \sqrt{4-y} from y=0y=0 to y=154y=\frac{15}{4} about the yy-axis. Choose the correct answer from the options provided.

See Solution

Problem 28652

Find the area of the surface formed by revolving the curve x=24yx=2 \sqrt{4-y}, for 0y1540 \leq y \leq \frac{15}{4}, around the y-axis.

See Solution

Problem 28653

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π3x=\frac{\pi}{3}. Choices: 2\sqrt{2}, 32\frac{\sqrt{3}}{2}, 32\sqrt{\frac{3}{2}}, 12\frac{1}{\sqrt{2}}, none.

See Solution

Problem 28654

Find the surface area generated by revolving y=x39y=\frac{x^{3}}{9}, for 0x20 \leq x \leq 2, around the x-axis.

See Solution

Problem 28655

Find the curve with positive slope passing through (1,2) and length L=141+4x2dxL=\int_{1}^{4} \sqrt{1+4 x^{2}} d x.

See Solution

Problem 28656

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4f(2)=4, f(4)=5f(4)=5, f(2)=13f^{\prime}(2)=\frac{1}{3}, f(5)=15f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28657

Find the length of the curve defined by x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} d t from y=π6y=-\frac{\pi}{6} to y=π6y=\frac{\pi}{6}. Options: 23\frac{2}{\sqrt{3}}, none, 1, 0, 232 \sqrt{3}.

See Solution

Problem 28658

Find the length of the curve x=0ysec4t1dtx = \int_{0}^{y} \sqrt{\sec^{4} t - 1} \, dt from y=π3y = -\frac{\pi}{3} to y=π6y = \frac{\pi}{6}.

See Solution

Problem 28659

Find the length of the curve x=0ysec4t1dtx = \int_{0}^{y} \sqrt{\sec^{4}t - 1} \, dt from y=π4y = -\frac{\pi}{4} to y=π4y = \frac{\pi}{4}.

See Solution

Problem 28660

Find the area of the surface formed by revolving y=x+1y=\sqrt{x+1} from x=1x=1 to x=5x=5 around the x-axis.

See Solution

Problem 28661

Find the surface area from revolving the curve x=y33x=\frac{y^{3}}{3}, 0y10 \leq y \leq 1 about the y-axis.

See Solution

Problem 28662

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π3x=\frac{\pi}{3}. Options: 12\frac{1}{\sqrt{2}}, 32\frac{\sqrt{3}}{2}, 32\sqrt{\frac{3}{2}}, 2\sqrt{2}.

See Solution

Problem 28663

Find the length of the curve defined by x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} d t from y=π6y=-\frac{\pi}{6} to y=π6y=\frac{\pi}{6}.

See Solution

Problem 28664

Find the surface area of the curve x=yx=\sqrt{y} from y=2y=2 to y=6y=6 when revolved around the yy-axis.

See Solution

Problem 28665

Find the surface area generated by revolving y=2x+1y=\sqrt{2x+1} from 0x30 \leq x \leq 3 about the x-axis.

See Solution

Problem 28666

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π2x=\frac{\pi}{2}.

See Solution

Problem 28667

Find the surface area generated by revolving x=4yy2x=\sqrt{4y-y^{2}} from y=1y=1 to y=2y=2 around the y-axis.

See Solution

Problem 28668

Find the surface area from revolving x=2y1x=\sqrt{2y-1}, 58y1\frac{5}{8} \leq y \leq 1 around the y-axis.

See Solution

Problem 28669

Find the length of the curve x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} \, dt from y=π6y=-\frac{\pi}{6} to y=π3y=\frac{\pi}{3}. Choices: 0, 10, 43\frac{4}{\sqrt{3}}, 232\sqrt{3}, none.

See Solution

Problem 28670

Find the curve with positive derivative and length L=141+4x2dxL=\int_{1}^{4} \sqrt{1+4 x^{2}} d x passing through (1,0)(1,0).

See Solution

Problem 28671

Find the length of the curve x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} dt from y=π6y=-\frac{\pi}{6} to y=π3y=\frac{\pi}{3}.

See Solution

Problem 28672

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4f(2)=4, f(4)=5f(4)=5, f(2)=13f^{\prime}(2)=\frac{1}{3}, f(5)=15f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28673

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π4x=\frac{\pi}{4}.

See Solution

Problem 28674

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4f(2)=4, f(4)=5f(4)=5, f(2)=13f^{\prime}(2)=\frac{1}{3}, f(5)=15f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28675

Find the length of the curve defined by y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π6x=\frac{\pi}{6}.

See Solution

Problem 28676

Find the surface area from revolving x=y33,0y1x=\frac{y^{3}}{3}, 0 \leq y \leq 1 around the y-axis.

See Solution

Problem 28677

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π6x=\frac{\pi}{6}.

See Solution

Problem 28678

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4f(2)=4, f(4)=5f(4)=5, f(2)=13f^{\prime}(2)=\frac{1}{3}, f(5)=15f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28679

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π6x=\frac{\pi}{6}.

See Solution

Problem 28680

Find the area of the surface generated by revolving y=x+1y=\sqrt{x+1}, for 1x51 \leq x \leq 5, around the x-axis.

See Solution

Problem 28681

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π3x=\frac{\pi}{3}.

See Solution

Problem 28682

Find (f1)(4)\left(f^{-1}\right)^{\prime}(4) given f(2)=4f(2)=4, f(4)=5f(4)=5, f(2)=13f^{\prime}(2)=\frac{1}{3}, f(5)=15f^{\prime}(5)=\frac{1}{5}.

See Solution

Problem 28683

Find the surface area generated by revolving x=yx=\sqrt{y} from y=2y=2 to y=6y=6 around the yy-axis.

See Solution

Problem 28684

Find the surface area of revolution for y=2x+1y=\sqrt{2x+1} from 00 to 33 about the xx-axis. Options: 14π23\frac{14 \pi \sqrt{2}}{3}, 28π23\frac{28 \pi \sqrt{2}}{3}, none, 28π3\frac{28 \pi}{3}, 28π228 \pi \sqrt{2}.

See Solution

Problem 28685

Find the surface area generated by revolving the curve x=yx=\sqrt{y} from y=2y=2 to y=6y=6 about the y-axis.

See Solution

Problem 28686

Find the surface area of the curve x=yx=\sqrt{y}, for 2y62 \leq y \leq 6, revolved around the y-axis.

See Solution

Problem 28687

Find the surface area from revolving x=y,2y6x=\sqrt{y}, 2 \leq y \leq 6 around the yy-axis. Choices include 49π6\frac{49 \pi}{6}, 98π18\frac{98 \pi}{18}, 98π6\frac{98 \pi}{6}, 49π81\frac{49 \pi}{81}, none.

See Solution

Problem 28688

Find the length of the curve defined by y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π6x=\frac{\pi}{6}.

See Solution

Problem 28689

Find the surface area from revolving x=y33,0y1x=\frac{y^{3}}{3}, 0 \leq y \leq 1 around the y-axis. Options include: 49π81(81)\frac{49 \pi}{81}(\sqrt{8}-1), 98π18(221)\frac{98 \pi}{18}(2 \sqrt{2}-1), none, π9(221)\frac{\pi}{9}(2 \sqrt{2}-1), π9(21)\frac{\pi}{9}(\sqrt{2}-1).

See Solution

Problem 28690

Find the curve with positive derivative and length L=141+4x2dxL=\int_{1}^{4} \sqrt{1+4 x^{2}} d x, passing through (1,0)(1,0).

See Solution

Problem 28691

Find the surface area from revolving y=2x+1y=\sqrt{2x+1}, 0x30 \leq x \leq 3, about the xx-axis. Choose the correct answer:
1. 14π23\frac{14 \pi \sqrt{2}}{3}
2. 28π23\frac{28 \pi \sqrt{2}}{3}
3. None
4. 28π3\frac{28 \pi}{3}
5. 28π228 \pi \sqrt{2}

See Solution

Problem 28692

Find the length of the curve defined by x=0ysec4t1dtx=\int_{0}^{y} \sqrt{\sec ^{4} t-1} d t from y=π4y=-\frac{\pi}{4} to y=π4y=\frac{\pi}{4}.

See Solution

Problem 28693

Find the curve with positive derivative and length L=141+4x2dxL = \int_{1}^{4} \sqrt{1 + 4x^2} \, dx passing through (0,1)(0,1). Choose one:
1. y=x2+1y = x^2 + 1
2. y=x21y = x^2 - 1
3. y=x2y = x^2
4. y=2xy = 2x
5. none

See Solution

Problem 28694

Find the surface area of the curve x=2y1x=\sqrt{2y-1}, for 58y1\frac{5}{8} \leq y \leq 1, revolved around the y-axis.

See Solution

Problem 28695

Find the surface area of the curve y=2x+1y=\sqrt{2x+1}, 0x30 \leq x \leq 3, rotated around the x-axis. Options: 14π23,28π23,none,28π3,28π2\frac{14 \pi \sqrt{2}}{3}, \frac{28 \pi \sqrt{2}}{3}, \text{none}, \frac{28 \pi}{3}, 28 \pi \sqrt{2}

See Solution

Problem 28696

Bestimmen Sie die Ableitungsfunktion ff^{\prime} und berechnen Sie f(2)f^{\prime}(2) für: a) f(x)=2x2f(x)=2 x^{2}, b) f(x)=4x2f(x)=4 x^{2}, c) f(x)=3x2f(x)=-3 x^{2}, d) f(x)=12x2f(x)=\frac{1}{2} x^{2}.

See Solution

Problem 28697

Find the length of the curve y=0xcos2tdty=\int_{0}^{x} \sqrt{\cos 2 t} d t from x=0x=0 to x=π3x=\frac{\pi}{3}.

See Solution

Problem 28698

Find the position s(t)s(t), displacement, and distance for the following velocity functions over [0,1][0,1]:
1. v(t)=4t25tv(t)=4 t^{2}-5 t, s(0)=5s(0)=5
2. v(t)=sin(t)v(t)=\sin(t), s(π)=2s(\pi)=-2

See Solution

Problem 28699

Find the surface area of the curve x=yx=\sqrt{y} from y=2y=2 to y=6y=6 revolved around the y-axis.

See Solution

Problem 28700

Find the surface area generated by revolving x=yx=\sqrt{y} from y=2y=2 to y=6y=6 around the yy-axis.

See Solution
banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ContactInfluencer programPolicyTerms
TwitterInstagramFacebookTikTokDiscord